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10th Dec 2009

How Would You Set Up This Algebraic Problem Solving Question?

Kacey and Starr found that if 3 times a number is decreased by 5 and this difference is doubled, the result is 14 less than twice the number. What is the number?
Please help, thanks.

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2 Responses to “How Would You Set Up This Algebraic Problem Solving Question?”

  1. David Says:

    Let n be the number you’re looking for. Just write out what the problem says and when you get to “the result is” put an equals sign.
    3 times a number = 3n
    decreased by 5 = 3n – 5
    double the difference = 2(3n – 5)
    twice the number = 2n
    14 less = 2n -14
    so, 2(3n – 5) = 2n – 14
    Now we solve the equation for n to find the number.
    1) 2(3n – 5) = 2n – 14 {multiply the 2 across the parentheses}
    2) 6n – 10 = 2n -14 {add 10 to both sides}
    3) 6n = 2n – 4 {subtract 2n from both sides}
    4) 4n = -4 {divide both sides by 4}
    5) n = -1
    That’s it!

  2. Ramzi Says:

    the equation is: 2(3n-5) = 2n-14
    6n-10 = 2n-14
    4n = -4
    n = -1 and this is the unswer

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